문자열 속의 숫자의 합

#include <stdio.h>
#include <stdlib.h>
 
int solution(char word[]) {
    int answer = 0, i, n = 0;
 
    for (i = 0; word[i] != '\0'; i++)
    {
        for (; word[i] >= '0' && word[i] <= '9'; i++)
        {
            n = n * 10 + (word[i] - 48);
        }
 
        answer += n;
        n = 0;
    }
    return answer;
}
 
int main(void)
{
    char word[81];
    int total;
 
    scanf("%s", word);
    total = solution(word);
    printf("%d\n", total);
 
    return 0;
}
 

 

 

 

결과: